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# When the equation o2 c5h12 o2 co2 h2o is balanced the ... The easiest way to remember how to solve combustion reactions is to know that CO2 and H2O are always the two resulting products. Energy is the third and final product however for the purposes of this question it is not necessary.

To balance the equation first write out the the reactants and the products Five on the left then five on the right. Next move to Hydrogen on the left, twelve on the left then 6 on the right. When you get to O2 you should just add up the total Oxygen on the right and divide by two and you will have your answer. Burning pentane, C5H12, is a combustion reaction in which pentane and oxygen will react to form carbon dioxide and water.

The coefficient of O2 is 5. The enthalpy associated with pentane is roughly 1 to 1 when combustion in a vacuum chamber, if you combustion it outside you will have a greater rate of loss from the pentane. The answer is C5H12 because the boiling points of hydrocarbons increase as the number of carbon atoms are increased and as a result the compound with the fewest carbon atoms is C5H Asked By Curt Eichmann. Chemical Bonding. Asked by Wiki User. Top Answer. Wiki User Answered Related Questions.Start with C5H Because the only thing that has Carbon C on the right side of the equation is CO2, then the coefficient for CO2 on the right side -must- be 5.

Then we can look at the H's, in the C5H Since the only thing with Os on the left side is O2, we can add an 8 coefficient there to get Look at the right side of the equation. You have 2 O's, 5 C's, and 12 H's. Look at the left side of the equation. You have 3 O's, 1 C, and 2 H's. Lets start with C.

## Balance this equation ( ? ) C5H12(l) + ( ? ) O2(g) -> ( ?) CO2(g) +( ? ) H2O(g) +energy?

Now lets move onto H. Finally, we balance O. We are now a balanced equation. Coefficients are multiplied by the subscripts of the elements.

It starts as a trial and error, but you'll get the hang of it once you do enough of them. Always take it one element at a time. And if the element appears more than once on either side of the reaction, save it until last, like O in this case. Hope this helps, good luck! In combustion reactions, its always best to leave oxygen for last.

The numbers can get pretty nasty for balancing so thats your best bet. Also, when I was learning to balance, I always made a chart right underneath the equationone on product side and one under reactants side, to keep track of all the numbers.

It works well, if you don't do it already. I balanced C first and made it 5 on product side. This made oxygen 11 on product side. Then I balanced H on product side, and added a coefficient of 6 to make it This made Hydrogen balance also, and it gave oxygen a 16 on product side.Balanced equation.

Therefore, youdo not need to add numbers infront of each compound. Hope this helped! In excess O2. Asked By Curt Eichmann. Asked By Roslyn Walter. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply. Ask Login. Asked by Wiki User. Top Answer. Wiki User Answered Related Questions. What is the balanced equation of incomplete combustion of pentane in air? Difficult write a balanced chemical equation incomplete combustion hydrocarbon?

Is the following equation balanced CO - C plus O2? What is the chemical equation for the gasification of coal? Equation for the formation of acetamide?

What is the chemical equation for the incomplete combustion of propane? How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce What is a balanced chemical equation for how a catalytic converter works?

What is the balanced equation of incomplete combustion of hexane in air? How carbon monoxide is decompose? What is the balanced chemical equation for CH3OH or carbon monoxide and hydrogen? What is the balanced chemical equation of sodium carbonate and cobalt nitrate?Let's first balance the carbons.

Now, let's balance the hydrogens. Final step is to balance the oxygens. There are two on the left hand side, but thirteen on the right hand side, so we need to divide thirteen by two to get the "scale number", which is 6. The equation is thus:. But wait, we cannot have half a molecule! So, we need to multiply the whole equation by 2which leads us to the finalized, balanced equation:.

We begin by counting the number of C atoms on both sides. We have 4 C on the left and 1C on the right.

Now count the number of H atoms on both sides.

## When the equation, ___O2 + ___C5H12 → ___CO2 + ___H2O is balanced, the coefficient: of O2 is:?

We have 10 H on the left and 2H on the right. Now, O 's turn. We have 2O on the left and 13O on the right. C color white wwwwwww 8 color white wwwwwwwwtwww 8. H color white wwwtwww 20 color white wwwwwwwwwww O color white wwwuwww 26 color white wwwwwwwwwww Nam D. Apr 7, Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules?

What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question views around the world. You can reuse this answer Creative Commons License.We are now a balanced equation.

Coefficients are multiplied by the subscripts of the elements. It starts as a trial and error, but you'll get the hang of it once you do enough of them. Always take it one element at a time.

And if the element appears more than once on either side of the reaction, save it until last, like O in this case. You can not change the subscripts, or else you are changing the substance itself. That would be counterproductive. To do this, you need to remember how to do ratios to an extent.

Really, you just need to multiply the given substance by the right amount to make them reach equilibrium. The reason you have to balance equations is due to the law of conservation of mass. So clearly, you need to multiply the right side by six to equal out the ratio for the hydrogen atoms because there are already two there.

Oygen is a bit tricky, but find the lowest common denominator between the two numbers. In this case, it is six. But you have another oxygen attached to H2 so you can't just take the easy way out.

Instead, you have to kind of trial and error it. On the right side, thanks to our efforts so far, we have sixteen oxygen atoms. On the left side, we have O2. To balance everything, simply multiply the left oxygen by eight. And viola, you are done! Update: how are you getting 16 for 0xygen.

Answer Save. Favorite Answer. Look at the right side of the equation. You have 2 O's, 5 C's, and 12 H's. Look at the left side of the equation. You have 3 O's, 1 C, and 2 H's.

How to Balance C7H17 + O2 = CO2 + H2O

Now lets move onto H. Finally, we balance O. Hope this helps, good luck! Once you get the hang of it, you can do this in no time. Remember these basic guidelines: 1. You must have the same amount of each type of atom on the left and the right. Yeah, that's it. Same thing with carbon, but with five. Remember, you can't change the basic substance. So to get 16 O on the left you need 8 O2. And if the O2 comes to a half, just double every coefficient to end up with whole numbers.

How do you think about the answers? You can sign in to vote the answer.We are now a balanced equation. Coefficients are multiplied by the subscripts of the elements. It starts as a trial and error, but you'll get the hang of it once you do enough of them. Always take it one element at a time. And if the element appears more than once on either side of the reaction, save it until last, like O in this case. You can not change the subscripts, or else you are changing the substance itself.

That would be counterproductive. To do this, you need to remember how to do ratios to an extent. Really, you just need to multiply the given substance by the right amount to make them reach equilibrium. The reason you have to balance equations is due to the law of conservation of mass. So clearly, you need to multiply the right side by six to equal out the ratio for the hydrogen atoms because there are already two there.

Oygen is a bit tricky, but find the lowest common denominator between the two numbers. In this case, it is six. But you have another oxygen attached to H2 so you can't just take the easy way out. Instead, you have to kind of trial and error it. On the right side, thanks to our efforts so far, we have sixteen oxygen atoms. On the left side, we have O2. To balance everything, simply multiply the left oxygen by eight. And viola, you are done!

### When The Equation O2 C5h12 O2 Co2 H2o Is Balanced The Coefficient Of O2 Is

Trending News. A warning sign for Trump at the Villages in Florida. Lucille Ball's great-granddaughter dies at Virginia health officials warn of venomous caterpillars. NBA star Kevin Love's honest talk about mental health.To perform a stoichiometric calculation, enter an equation of a chemical reaction and press the Start button. First, be sure to count all of C, H, and O atoms on each side of the chemical equation.

Ahora determinas las masas de cada una de las sustancias participantes. The salinity effect in a mixed layer ocean model. Finally, we balance O. Balance the atoms that occur in compounds before attempting to balance atoms that occur in elemental form. If a coefficient of "1" is required, choose "blank" for that box.

To balance a chemical equation, one must keep track of the atoms on each side of the equation as you change the coefficients in front of each component. Finally, we have to balance the oxygens. Here are some related questions which you might be interested in reading. The coefficients in the balanced equation determine the ratio of moles of reactants to moles of products. Balance the following equation. This method is most useful when there are only two reactants. How To Balance Equations.

This equation does not have any coefficients in front of CH 4 and CO 2, since a coefficient of 1 is dropped. Determine the balanced chemical equation for this reaction. Most O2 combines with carbon and hydrogen atoms from glucose molecules to form cellular energy, known as adenosine triphosphate or ATP, along with carbon dioxide CO2 and water.

Now lets move onto H. Compound states [like s aq or g ] are not required. Even though none of the terms in this example are electrically charged, we always add an equation for electric charge anyway. First, be sure to count all of C, H, and O atoms on each side of the chem.

You can use parenthesis or brackets []. Write a balanced chemical equation for this reaction and explain the scientific principle statement that requires the balancing of an equation to make it conform to reality.